Frost essays

Frost essays With a Colt pistol pointed dead at the doctor, threatening to shoot if anything happened to his expecting wife, a very erratic William Frost welcomed his son Robert Lee Frost into the world in San Francisco California on March 26, 1874. Frost was named part after his grandfather and after the defeated Civil war general Lee. Thinking that he was the product of a premarital mistake, Robert tried to hide it by saying he was born a year after, in 1875. In the beginning, William was happy with his son, but as his health began to spoil and he took to the bottle. William felt very burdened with his family and would constantly abuse them. Robert, through all the torment and abuse, stuck close to his mother who tried to make up for her husbands abuse by pampering her son. After the death of his father from tuberculosis, Frosts mother, Isabelle, moved Robert and his sister Jeanie to Lawrence, Massachusetts. In 1892, Robert graduated with honors from his high school and was valedictorian along with Elinor White, which was his high school love. After high school Robert went to Dartmouth College and persued a career in poetry. In 1894, he succeeded in having his fist professional publication. The Independent, a literary journal, published his poem My Butterfly: An Elegy. He soon after left college and married his high school sweetheart, Elinor. With his family growing, Frost struggled to get by. Robert and Elinor had six children in total and two died at an early age leaving Frost with one son and three daughters. In 1897, Frost resumed college at Harvard, but he left within two years. In order to support his family, Robert Frost raised poultry on a farm in New Hampshire and he was also teaching at the Pinkerton Academy in Derry. During his days in New Hampshire, Frost became a botanist and took on the New England persona in his writings. Still trying to get his writings published, Frost realized that the A...

How to Determine the Equation of a Line

How to Determine the Equation of a Line There are many instances in science and math in which you will need to determine the equation of a line. In chemistry, youll use linear equations in gas calculations, when analyzing rates of reaction, and when performing Beers Law calculations. Here are a quick overview and example of how to determine the equation of a line from (x,y) data. There are different forms of the equation of a line, including the standard form, point-slope form, and slope-line intercept form. If you are asked to find the equation of a line and are not told which form to use, the point-slope or slope-intercept forms are both acceptable options. Standard Form of the Equation of a Line One of the most common ways to write the equation of a line is: Ax By C where A, B, and C are real numbers Slope-Intercept Form of the Equation of a Line A linear equation or equation of a line has the following form: y mx b m: slope of the line; m Δx/Δy b: y-intercept, which is where the line crosses the y-axis; b yi  - mxi The y-intercept is written as the point  (0,b). Determine the Equation of a Line Determine the equation of a line using the following (x,y) data. (-2,-2), (-1,1), (0,4), (1,7), (2,10), (3,13) First calculate the slope m, which is the change in y divided by the change in x: y Δy/Δx y [13 - (-2)]/[3 - (-2)] y 15/5 y 3 Next calculate the y-intercept: b yi  - mxi b (-2) - 3*(-2) b -2 6 b 4 The equation of the line is y mx b y 3x 4 Point-Slope Form of the Equation of a Line In the point-slope form, the equation of a line has slope m and passes through the point (x1, y1). The equation is given using: y - y1 m(x - x1) where m is the slope of the line and (x1, y1) is the given point Determine the Equation of a Line Find the equation of a line passing through points (-3, 5) and (2, 8). First determine the slope of the line. Use the formula: m (y2 - y1) / (x2 - x1)m (8 - 5) / (2 - (-3))m (8 - 5) / (2 3)m 3/5 Next use the point-slope formula. Do this by choosing one of the points, (x1, y1) and putting this point and the slope into the formula. y - y1 m (x - x1)y - 5 3/5 (x - (-3))y - 5 3/5 (x 3)y - 5 (3/5)(x 3) Now you have the equation in point-slope form. You could proceed to write the equation in slope-intercept form if you wish to see the y-intercept. y - 5 (3/5)(x 3)y - 5 (3/5)x 9/5y (3/5)x 9/5 5y (3/5)x 9/5 25/5y (3/5)x 34/5 Find the y-intercept by setting x0 in the equation of the line. The y-intercept is at the point (0, 34/5).